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			<title>Question: : 88473479457836429+8743974487539573957495749+9733974937943749=?</title>
			  <link>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D</link>
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			  <pubDate>Tue, 19 Jan 2021 13:12:30 +0000</pubDate>
			  <category>電腦及互聯網</category>
			  <author>guest@oegod.com (匿名 匿名)</author>
			  <comments>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D</comments>
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			  <title>Answer for: 88473479457836429+8743974487539573957495749+9733974937943749=?</title>
			  <link>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D#answer-693</link>
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			  <description>有陷阱?

如果沒有的話, 直接加總就是了.

8743974585747028353275927

如果是要寫程式, 就是擷取每個數位的數字, 然後由

低位開始做運算, 直至最高數位. 當然也可考慮每 k

位一節的方式.</description>
			  <pubDate>Fri, 19 Mar 2021 07:38:30 +0000</pubDate>
			  <category>電腦及互聯網</category>
			  <author>guest@oegod.com (匿名 匿名)</author>
			  <comments>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D#answer-693</comments>
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			  <title>Answer for: 88473479457836429+8743974487539573957495749+9733974937943749=?</title>
			  <link>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D#answer-694</link>
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			  <description>沒有陷阱，只是考數學，如果你沒有計錯就是對的</description>
			  <pubDate>Wed, 06 Jan 2021 12:47:30 +0000</pubDate>
			  <category>電腦及互聯網</category>
			  <author>guest@oegod.com (匿名 匿名)</author>
			  <comments>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D#answer-694</comments>
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			  <title>Answer for: 88473479457836429+8743974487539573957495749+9733974937943749=?</title>
			  <link>https://www.oegod.com/question/88473479457836429%2B8743974487539573957495749%2B9733974937943749%3D#answer-695</link>
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			  <description>應該沒有這項問題的解答... ... ... ... ...</description>
			  <pubDate>Tue, 16 Feb 2021 23:52:30 +0000</pubDate>
			  <category>電腦及互聯網</category>
			  <author>guest@oegod.com (匿名 匿名)</author>
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